What is the derivative of the absolute value of cos(x)?

In summary, the derivative of the absolute value of cos(x) is -sin(x)*sgn(cos(x)). The 'sign' or 'signum' function, which returns 1 or -1, can be defined by sgn(x)=|x|/x for nonzero x, and is zero when x is zero. However, it cannot be used in this case as |\cos(x)| is not differentiable at the values of x for which \cos(x)=0. The derivative of the signum function can be determined by looking at its graph. Higher order derivatives of the signum function can also be found in a similar manner.
  • #1
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What is the derivative of the absolute value of cos(x)?
 
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  • #2
The derivative of cos(x) is -sin(x) and the derivative of |x| is sgn(x), can you now combine them?
 
  • #3
Thanks, but what does sgn stand for? Is the derivative just -sin(x)*Abs(cos(x))'?
 
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  • #4
The 'sign' or 'signum' function, which returns 1 or -1, whether the argument in question was positive or negative.

See http://mathworld.wolfram.com/Sign.html" .
 
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  • #5
[tex]\frac{d}{dx}|\cos(x)|=-\frac{|\cos(x)|}{\cos(x)}\sin(x)[/tex]
Note that the signum function can be defined by [tex]sgn(x)=\frac{|x|}{x}[/tex] for nonzero x, and is zero when x is zero. The signum function cannot be use in this case as [tex]|\cos(x)|[/tex] is not differentiable at the values of x for which [tex]\cos(x)=0[/tex] as the lefthand and righthand derivative are not equal there (by lefthand or righthand derivates, what is meant is the left or right-handed limit of the difference quotient at a particular value of x).
 
  • #6
Thank you so much. I've never even heard about the signum function before until now. How would I go about taking higher order derivatives of the signum function like the second and third, etc. How does that work?
 
  • #7
Look at its graph. The derivative should be apparent.
 

1. What is the definition of the derivative of absolute value of cos(x)?

The derivative of absolute value of cos(x) is the rate of change of the function at a specific point. It is the slope of the tangent line to the graph of the function at that point.

2. How is the derivative of absolute value of cos(x) calculated?

The derivative of absolute value of cos(x) is calculated by using the chain rule. The derivative of absolute value of cos(x) is equal to the derivative of cos(x) multiplied by the derivative of the absolute value of x.

3. What is the derivative of absolute value of cos(x) at x=0?

The derivative of absolute value of cos(x) at x=0 is equal to 0. This is because the graph of the function has a sharp point at x=0, and the slope of the tangent line at a sharp point is always 0.

4. Can the derivative of absolute value of cos(x) be negative?

Yes, the derivative of absolute value of cos(x) can be negative. This happens at points where the slope of the tangent line to the graph of the function is negative. This occurs when the value of x is between -π/2 and π/2.

5. What is the relationship between the derivative of absolute value of cos(x) and the derivative of cos(x)?

The derivative of absolute value of cos(x) is equal to the derivative of cos(x) multiplied by the sign of cos(x). This means that the derivative of absolute value of cos(x) is equal to the derivative of cos(x) when cos(x) is positive, and equal to the negative of the derivative of cos(x) when cos(x) is negative.

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