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What is the distance of the image?

  1. Aug 6, 2005 #1
    An object is located 19.5 cm from a converging mirror with a focal length of 5.5 cm. What is the distance of the image? Is it real or virtual? Is it smaller or larger than the object? Is it upright or inverted?
    This is the equation I need to use for the problem
    1/object-mirror distance + 1/image-mirror distance= 1/mirror"s focal lenth to solve for image-mirror distance
    This is how I solved for the problem
    1/image-mirror distance = 1/5.5 - 1/19.5 = .1305361305 then I have to find the reciprocal which is 1/.1305361305 = 7.660714288 or 7.66cm
    Have I solved this correctly?
  2. jcsd
  3. Aug 7, 2005 #2
    It's farther than the focal point, which immediately tells you that it's real and inverted.

    but i believe you have solved correctly
    remember, magnification is Di/Do
  4. Aug 7, 2005 #3
    Okay, then when it's closer than the focal point, does that mean that it's virtual and upright?
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