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What is the distance of the image?

  • Thread starter brayrbob
  • Start date
24
0
An object is located 19.5 cm from a converging mirror with a focal length of 5.5 cm. What is the distance of the image? Is it real or virtual? Is it smaller or larger than the object? Is it upright or inverted?
This is the equation I need to use for the problem
1/object-mirror distance + 1/image-mirror distance= 1/mirror"s focal lenth to solve for image-mirror distance
This is how I solved for the problem
1/image-mirror distance = 1/5.5 - 1/19.5 = .1305361305 then I have to find the reciprocal which is 1/.1305361305 = 7.660714288 or 7.66cm
Have I solved this correctly?
 

Answers and Replies

138
0
It's farther than the focal point, which immediately tells you that it's real and inverted.

but i believe you have solved correctly
remember, magnification is Di/Do
 
24
0
Okay, then when it's closer than the focal point, does that mean that it's virtual and upright?
 

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