# What is the electric potential

• elrohir00
In summary, you need to place an extra charge in the third corner of a triangle to make the centre have an electric field. The electric field is a vector field and is found by vector addition.
elrohir00
Hi,
i have 2 questions for electromagnitism and i just can't do them. my lecturer is just not up to the job of teaching and everyone is struggling and its probably something easy. anyway rant over.

1) you have an equlateral trinagle with chare q in 2 corners. what charge would you have to put into the third corner so the centre has
a)0 electric field
b)0 electric potential

in part a) what is the electric potential
in part b) what is the electic field

for this i have just been plating with trigonomatry and it just seems to longwinded for an answer that just doesn't seem right.

2) state how electric field can be calculated by electric potential.
the electric potential at derpendicular distance r from a long straight wire with cross section a is

v(r)=-k ln (r/a)

k is constant. calculate electric field as a function of r.

i know this is to do with intergrating or differentiating but not sure which.

if someone would be so kind to answer these and also give some details on elecromagnitism as a whole that would be amazing.

THANKS ALL

electromagnitism

## Homework Statement

there are 2 questions to this.
1) you have a equlateral triangle with 2 charged particles q in the corners. by choseing the third particle make the centre of the triangle have 0
a)field
b)porential
in case a what is the potential in case b what is the field.

## Homework Equations

my lecturer isn't the best in the world but i think these are the formulae
E=q/r
v=q^2/r
some trig?

## The Attempt at a Solution

i have just been playing around with trig to get the r value then doubling it as there are 2 charge q then thring to exuate it to a mystery charge.

thanks for any insite I am going off to get a book to try and help me along with this as my lecturer is just not worth while

Let's start with question (a). Can you write an expression for the electric field at the centre of the triangle in terms of their charges and position?

The electric field is a vector field and the total vector field is found by vector addition. Find the fields magnitude and direction due to the first two charges and work out what charge you will need to cancel it out. Electric potential due to a load of point charges is just the sum due to the individual point charges.

For part 2, remember that a conservative vector field is the gradient of a scalar potential function.

I merged the two threads, based on thread titles and problem statement.

ok i think for a

the charge will be q due to symetry
the distance r between to corner and centre is the same so if the extra one has the same charge it will just all cancal out.

b)

0=kq/r+kq/r+kQ/r
rearanged and simplifed
Q=-2q

now with the extra charges the rest should fall into place.

Yes, looks ok to me.

## What is the electric potential?

The electric potential is a measure of the potential energy per unit charge at a specific point in an electric field. It is also known as voltage and is represented by the symbol V.

## How is electric potential different from electric field?

While electric field represents the magnitude and direction of the force experienced by a charged particle, electric potential represents the potential energy that the particle has due to its position in the electric field. In other words, electric potential is a scalar quantity while electric field is a vector quantity.

## What are the units of electric potential?

The SI unit of electric potential is volts (V), named after Italian physicist Alessandro Volta. One volt is equal to one joule per coulomb (J/C).

## Can electric potential be negative?

Yes, electric potential can be negative. This indicates that the potential energy of a charged particle is decreasing as it moves towards a more positive source charge. Conversely, a positive electric potential indicates that the potential energy is increasing as the particle moves towards a more negative source charge.

## How is electric potential calculated?

The electric potential at a specific point in an electric field can be calculated by dividing the work needed to move a unit positive charge from infinity to that point by the magnitude of the charge. Mathematically, it can be expressed as V = W/q, where V is the electric potential, W is the work done, and q is the magnitude of the charge.

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