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What is the final temperature?

  1. Jan 31, 2008 #1
    A cup made of 100g of aluminum holds 200g of water at 50deg C, a 10g piece of ice is placed in the cup of water, what is the final temperature?

    2. Relevant equations
    S=cm lnTf/Ti
    specific heat of aluminum 0.90 J/gC

    3. The attempt at a solution
    I think the first step is to determine S(ice)
    Q=Lm=79.5 cal/g * 10g=795cal

    then as 0deg C water goes to 50deg C?
    I believe I should be using an integral as the ice will be changing the temp of the water?
    1cal/gC * 10g ln(795/323)=9

    1cal/gC*200 ln(795/323)=180

    So now I'm confused-because I believe I would need to know the final temp of the water before calculating S with the Steel??
    I also do not understand how to convert J/gC to cal
  2. jcsd
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