Problem: A long vertical wire carries a steady 17 A current. A pair of rails are horizontal and are 0.2 m apart. A 7.6 Ω resistor connects points a and b, at the end of the rails. A bar is in contact with the rails, and is moved by an external force with a constant velocity of 0.5 m/s as shown. The bar and the rails have negligible resistance. At a given instant t1, the bar is 0.18 m from the wire, as shown. In Figure, at time t1, the induced current in µA is:(adsbygoogle = window.adsbygoogle || []).push({});

Express the answer in three decimal places.

My attempt at the question:

Current in the wire, i = 17 A

Distance between the rails, d = 0.20 m

Resistance, R = 7.6 Ω

Velocity , v = 0.50 m/s

At time t1, the bar is 0.18 m from the wire

B = μ0 i / 2 π d

= (4 π *10-7 T.m/A) (17 A) / 2π (0.20 m)

B = 1.7 *10-5 T

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Induced emf , ε = dφ / dt

= B L v

= (1.7 *10-5 T) (0.18 m) (0.50 m/s)

= 1.53 *10-6 V

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Induced current, I = ε / R

= (1.53 *10-6 V) / (7.6 Ω)

= 2.01 *10-7 A

= 0.201 μ A

It seems to be wrong so I don't exactly know what I'm doing wrong so could someone help me out?

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# Homework Help: What is the induced current?

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