what is the integral of lnx?
Try writing it as 1*ln(x), then integrate by parts. (Should get x*ln(x)-x).
could you show me the entire way?
du/dx = 1
v = ln(x)
u = x
dv/dx = 1/x
Now, integrating by parts:
∫1*ln(x)dx = u*v - ∫u*dv/dx
= x*ln(x) - ∫dx
= x*ln(x) - x (+ C to be pedantic)
i got it, thanks.
edit: just one problem should this ∫u*dv/dx=∫1
lonewolf i think i am wrong but i need your verification on that.
never mind i found my mistake.
Oops, sorry LQG, I wasn't ignoring you intentionally. Glad you figured it out anyway
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