# A What is the Lorentz time transformation?

Tags:
1. Dec 26, 2016

### pigy

$t'=\gamma(t-xv/c^2)$

So, what is this?

My attempt to resolve this problem.

The transform of the spatial part is: $x'=\gamma(x-vt)$

therefore the light speed must be transformed to the:
$c'=\gamma(c-v)$

additionaly: a light ray equatin is: x = ct, thus: x' = c't accordingly.

But because the additionali relativistic assumption: c = inv,
the light ray equation should be written in other way: x' = ct'

Thus the relativity convence proposes nothing other but just that :
$c't = ct'$
so, the relativistic convention c = inv, implies a time transform in the form:
$t'=c'/c t=\gamma(c-v)/c t=\gamma(1-v/c) t=\gamma(t-t v/c)$

but: x = ct => t = x/c, thus somebody can use, replace the t by x/c:
$t'=\gamma(t- xv/c^2)$
this is exactly the Lorentz's time transformation.
It's an unrealistic - artificial thing only.