for a normalized distribution function f(p) over a finite interval I,(adsbygoogle = window.adsbygoogle || []).push({});

f(p) >= 0,

Int f(p) dp (over I) = 1

the standard deviation is given by the square root of

<p^2> - <p>^2

= Int p^2 f(p) dp - (Int p f(p) dp)^2

how to find the lowest upper bound (if exists) of the standard deviation?

Variational Calculus?

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# What is the lowest upper bound of standard deviation

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