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What is the magnitude of the runner's total displacement?

  • Thread starter thschica
  • Start date
  • #1
47
0
A football player runs directly down the field for 35 m before turning to the right at an angle of 25 degrees from his original direction and running an additional 15 m before getting tackled. What is the magnitude of the runner's total displacement?

I got 38.08 but it is not right can someone tell me how to do it?
 

Answers and Replies

  • #2
2,209
1
One vector pointing straight north has magnitude 35m, then another vector pointing 25 degrees to the right of north (65 north of east) has magnitude 15m, find the vector sum.
 
  • #3
47
0
Is the vector sum 50 meters?How do you get it?
 
Last edited:
  • #4
mrjeffy321
Science Advisor
875
1
Perhaps drawing the situation might help.

Then find the over all change in position that occured as if he ran in a straight line the entire distance.
 
  • #5
2,209
1
You might want to break down components, your vectors looks like this

[tex] \vec{x_1} = <35,0> [/tex]

[tex] \vec{x_2} = <15\cos(25), 15\sin(25)> [/tex]
 
  • #6
47
0
Thank you I just got the answer right (49)
 
  • #7
HallsofIvy
Science Advisor
Homework Helper
41,833
955
That can't be the correct answer, as you phrased the problem. "Displacement" is a vector, not a number so no number could be the correct answer. 49 m (not just "49") might well be the magnitude of the displacement.
 

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