What is the mass of the cup?

  • Thread starter jincy34
  • Start date
  • #1
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Homework Statement



A 105.05 g ice cube at -15°C is placed in an aluminum cup whose initial temperature is 73°C. The system comes to an equilibrium temperature of 24°C. What is the mass of the cup?

Homework Equations


Q=mc (delta T)


The Attempt at a Solution



the sum of total heat in the system is equal to zero.
Qice+Qaluminium cup=0
MiceCice(delta T)+MaluminiumCaluminium(delta T)=0
I solved for mass of aluminium cup, and got 0.1951 kg. But, it is wrong.
Please help.
 

Answers and Replies

  • #2
hage567
Homework Helper
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Since the ice melts, I think you need to take into account the heat of fusion, Q=mL, where m is the mass of the ice and L is the latent heat of fusion.

Try that.
 
  • #3
20
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I did, and got 0.8633 kg. But, that is wrong too.
 
  • #4
hage567
Homework Helper
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You need to include terms for:
the heat required to bring the ice from -15 degrees to 0 degrees
the heat of fusion to melt the ice at 0 degrees to water at 0 degrees
the heat required to bring the water at 0 degrees to water at the final temperature of 24 degrees

This will be equal to the heat the aluminum cup loses.
 
  • #5
20
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Thank you very much.
 

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