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pinky2468
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I have a question from my practice test that is supposed to be on our midterm, so I want to make sure I am doing it right!
A 10kg projectile is launched from the wall of a canyon at an angle of 30 degrees above the horizon with a velocity of 100m/s. The wall is 1500m above the canyon floor.
a)what is the maximum height achieved by the projectile?
b)what is the impact velocity with the canyon floor?
So, I did part a and I found the x and y components of v...vsin30 and vcos30.
I then found the time and used it it the equation y=Voyt + 1/2at^2 and I got y=128m
So, for part b which equation do I use? If I use pythagorean theorem the answer is 100m/s which is the same as the initial. Is that right? Or do I need to use a different equation?
A 10kg projectile is launched from the wall of a canyon at an angle of 30 degrees above the horizon with a velocity of 100m/s. The wall is 1500m above the canyon floor.
a)what is the maximum height achieved by the projectile?
b)what is the impact velocity with the canyon floor?
So, I did part a and I found the x and y components of v...vsin30 and vcos30.
I then found the time and used it it the equation y=Voyt + 1/2at^2 and I got y=128m
So, for part b which equation do I use? If I use pythagorean theorem the answer is 100m/s which is the same as the initial. Is that right? Or do I need to use a different equation?