When what is near B? When A is near B? A and B are given, you can't move them.I guess that it would be when it is near B, because it is under constant acceleration.
When the object moving from A to B is near B, because it is under a constant acceleration.When what is near B? When A is near B? A and B are given, you can't move them.
It is a very simple question - if you want to get there ASAP, and your speed is limited only by the speed of light, what speed do you have to go at (as near as possible)?
Sorry, but I have no idea what you are trying to say.When the object moving from A to B is near B, because it is under a constant acceleration.
Yes.To answer your question, it would be as near as [possible to] the speed of light.
I'll try to explain myself better. The objecc is moving from A to B, starting at rest with a constant acceleration a until it reaches B. So the fastest the object will be travelling would be when it gets to point B.Sorry, but I have no idea what you are trying to say.
My comment about relativity and infinite speed was in the context of the constant speed case.The objecc is moving from A to B, starting at rest with a constant acceleration a
So, if in the case of constant speed, the object speed must be near the speed of light.My comment about relativity and infinite speed was in the context of the constant speed case.
For constant acceleration it gets a bit tricky. Not sure what that means within relativity.
I asked my teacher today. He said that indeed it start ar rest and accelerates at a and at somep point it decelerate at a in order to be at rest at B. He said that there arte two cases and that I need to choose one and explain why. So yes, I can use SUVAT equations. Which are the two cases?You seem to be making this problem much harder than it is. I very much doubt they intended you to think about limitations due to the speed of light!
It starts from A at rest and accelerates at "a". At some point it must stop accelerating and start to decelerate at "a" in order to be at rest at B.
A few basic equations of motion (eg SUVAT) and you are done.
Pity that wasn't stated in the first place.it start ar rest and accelerates at a and at somep point it decelerate at a in order to be at rest at B
Unless there is also a max allowed speed, I can only think of one case.Which are the two cases?
Given the clarification that it starts and finishes at rest, I don't see how that can be a sensible case.1) constant velocity gets there in the least amount of time
Effectively turning it into this model:I think choosing a "case" means arbitrarily picking either "cv wins" or "acc/dec wins", then working backwards to state the condition(s) that makes it so.
...maybe.If we were given a max speed the answer would depend on the relationship between that, the acceleration a and the distance.