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Introductory Physics Homework Help
What is the maximum volume expansion coefficient of ?
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[QUOTE="castrodisastro, post: 4641995, member: 491977"] [h2]Homework Statement [/h2] You are building a device for monitoring ultracold environments. Because the device will be used in environments where its temperature will change by [B]211°C[/B] in [B]2.99s[/B], it must have the ability to withstand thermal shock (rapid temperature changes). The volume of the device is [B]3.00⋅10[SUP]−5[/SUP]m[SUP]3[/SUP][/B], and if the volume changes by [B]1.00⋅10[SUP]−7[/SUP]m[SUP]3[/SUP][/B] in a time interval of [B]7.15s[/B], the device will crack and be rendered useless. What is the maximum volume expansion coefficient that the material you use to build the device can have? [B]ΔT[/B] = 211 °C [B]V[SUB]0[/SUB][/B] = 3.00⋅10[SUP]-5[/SUP] m[SUP]3[/SUP] [B]ΔV[/B] = 1.00⋅10[SUP]-7[/SUP] m[SUP]3[/SUP] [B]β[/B] = ? [h2]Homework Equations[/h2] [B]ΔV = β(ΔT)V[SUB]0[/SUB][/B] [h2]The Attempt at a Solution[/h2] It seems like I am given everything to calculate the volume expansion coefficient, β. I am not sure how the time limit of 2.99 s comes into play here if it takes us longer than 2.99 s for the temperature to change so the risk of thermal shock is avoided and seems like extra information and not something I need to take in account. I realize I may be wrong and want to understand why. I rearranged to solve β β = (ΔV)/(ΔT)(V[SUB]0[/SUB]) β = (1.00⋅10[SUP]-7[/SUP] m[SUP]3[/SUP])/(211 °C)(3.00⋅10[SUP]-5[/SUP] m[SUP]3[/SUP]) β = 1.5798⋅10[SUP]-5[/SUP] I submitted this problem to my online homework and I was incorrect. Any help would be appreciated. [/QUOTE]
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Introductory Physics Homework Help
What is the maximum volume expansion coefficient of ?
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