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## Main Question or Discussion Point

A tank of large area is filled with water to a depth of 0.6m. A hole of 6m^2 cross section in the bottom allows water to drain out in a continous stream. What is the rate at which water flows out the tank in m^3/s?

This is how I figure the problem should be solved:

Q= pi*r^4(p1-p2)/8L*viscosity

Area= 6e-4m^2

h= 0.6m

P= rho*g*h= 1.00e3kg/m^3*9.8m/s^2*0.6m= 5880N/m^2

what I can't figure out is how do I get viscosity from the area

This is how I figure the problem should be solved:

Q= pi*r^4(p1-p2)/8L*viscosity

Area= 6e-4m^2

h= 0.6m

P= rho*g*h= 1.00e3kg/m^3*9.8m/s^2*0.6m= 5880N/m^2

what I can't figure out is how do I get viscosity from the area