- #1

- 18

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This is how I figure the problem should be solved:

Q= pi*r^4(p1-p2)/8L*viscosity

Area= 6e-4m^2

h= 0.6m

P= rho*g*h= 1.00e3kg/m^3*9.8m/s^2*0.6m= 5880N/m^2

what I can't figure out is how do I get viscosity from the area

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- Thread starter lovelylm1980
- Start date

- #1

- 18

- 0

This is how I figure the problem should be solved:

Q= pi*r^4(p1-p2)/8L*viscosity

Area= 6e-4m^2

h= 0.6m

P= rho*g*h= 1.00e3kg/m^3*9.8m/s^2*0.6m= 5880N/m^2

what I can't figure out is how do I get viscosity from the area

- #2

Doc Al

Mentor

- 45,254

- 1,614

Forget viscosity. (Unless they want you to include it; in which case: Lot's of luck!) Assume laminar flow. Apply Bernoulli's principle. Hint: Since the tank has a "large area", ignore the 1/2ρV

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