What is the sigma bond count for 2 hydrogen in sulfuric acid?

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I tried to use VSERP to draw the shape of H2SO4
but consider
S :6 (group6)
4O :2*4
2H :1*2
-----------
16=>4pi bond
but then 4 pi bond of oxygen=16 electrons
how about the sigma bond of 2 hydrogen
 
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From memory SO4(-2) has the S as the central atom, two O's oppositely have a pi bond, and the remaining two have sigma bonds each with a negative charge. The H's are attached to these O's.
 
thunderfvck said:
From memory SO4(-2) has the S as the central atom, two O's oppositely have a pi bond, and the remaining two have sigma bonds each with a negative charge. The H's are attached to these O's.
but then it becomes
S:6
2O:1*2(sigma)
2O:2*2(pi)
2H:1*2
----------
14
but 2pi+4sigma=16
again, it does not work
 
Hint: Look at your electron count and then look at the charge on sulfuric acid.