What is the speed of a proton after moving in a uniform electric field?

NeoKrypt
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A uniform electric field has a magnitude of 3.0x10^3 N/C. In a vacuum, a proton begins with a speed of 2.3x10^4 m/s and moves in the direction of this field. Find the speed of the proton after it has moved a distance of .003 m.

I try to work out the problem with the equation F=qE to find the acceleration and plug that into a kinematics equation, but I do not have q. Can anyone help?
 
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You are told it is a proton, so it has a charge equal in magnitude to an electron (with opposite sign). 1.6*10^-19 C, I think. You should look it up in your textbook.
 
ah got it! I actually tried that just before I posted on here except I left the negative sign on the charge. Thanks a lot!
 

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