- 202

- 0

I came across with a problem in my question book which was

"what is the stoping voltage when a UV ligh with WaveLength 200nm hits a clean gold surface.(5.1v Work Function.)"

I have found the frequency which is [tex]1.5^15 Hz[/tex] I know the [tex]W[/tex] Therefore I can let [tex]Ekmax=(hf)-W[/tex] and [tex]Ekmax=qV[/tex]

But when I put the equations together they dont make any sence to me.

[tex]V=\frac{(hf)-W}{q}[/tex]

Can someone help me through this plz