What is the stoping voltage

  • Thread starter bayan
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  • #1
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Hi everyone.

I came across with a problem in my question book which was

"what is the stoping voltage when a UV ligh with WaveLength 200nm hits a clean gold surface.(5.1v Work Function.)"


I have found the frequency which is [tex]1.5^15 Hz[/tex] I know the [tex]W[/tex] Therefore I can let [tex]Ekmax=(hf)-W[/tex] and [tex]Ekmax=qV[/tex]

But when I put the equations together they dont make any sence to me.
[tex]V=\frac{(hf)-W}{q}[/tex]

Can someone help me through this plz
 

Answers and Replies

  • #2
dextercioby
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1.You should have posted this in the homework section.

2.Why don't they make any sense?

It looks okay so far.

Daniel.
 

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