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What is the temperature of the bath?

  1. Oct 3, 2005 #1
    At 50 degrees Celsius, the resistance of a segment of gold wire is 54. When the wire is placed in a liquid bath, the resistance increases to 189. The temperature coefficient is 0.0034 (degrees Celsius)^-1 at 20 degrees Celsius.
    What is the temperature of the bath? Answer in units of degrees Celsius.
     
  2. jcsd
  3. Oct 3, 2005 #2

    Tide

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    What have you done so far?
     
  4. Oct 4, 2005 #3
    I tried to use the equation:
    p-po = (po)a(T-To)
    To= reference temperature
    po= resistivity at that temperature
    a= temperature coefficient of resistivity

    So I did:
    189-54 = (54)(0.0034)(T-50)

    But I know the answer I got that way is wrong.
     
  5. Oct 4, 2005 #4

    CarlB

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    It sure looks to me like you've got the right equation. Are you sure you solved it correctly?

    The form of the equation that I am familiar with is

    [tex]R = \alpha T[/tex]

    where T is given in degrees Kelvin. But this reduces to your form in either degrees K or degrees C (or F).

    Carl
     
  6. Oct 4, 2005 #5
    When I use the formula I mentioned above, I get T=785.29 degrees Celsius. I don't know if I solved it incorrectly but I did:
    189-54=(54)(0.0034)(T-50)
    135=(0.1836)(T-50)
    735.29=T-50
    T= 785.29
     
  7. Oct 4, 2005 #6

    CarlB

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    Sure looks right to me. But that's a mighty hot bath. Maybe a molten salt bath.

    Carl
     
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