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What is the Unknown Temp (T) in TL-TR Equation?
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[QUOTE="Miike012, post: 4489262, member: 265497"] The Question is in the paint document. My question to this problem is at the bottom of thread 1 Equation: T = T[SUB]3[/SUB]/P[SUB]3[/SUB]P. Where T[SUB]3[/SUB] is the temperature (K) of water at triple point I am not 100% sure what P and P[SUB]3[/SUB] stand for (can someone tell me) I believe P is the net pressure (Pressure supplied by the bulb minus the pressure opposing the pressure supplied by the bulb) and P[SUB]3[/SUB] is the pressure at triple point. Solution: All Temp are in Kelvin (K) Define: T[SUB]L[/SUB] = Temp of left bulb P[SUB]L[/SUB] = Pressure of left bulb T[SUB]R[/SUB] = Temp of right bulb P[SUB]R[/SUB] = Pressure of right bulb First Step: Let T[SUB]L[/SUB] = T[SUB]3[/SUB] and T[SUB]R[/SUB] = Boiling Point of Water = (BP) T[SUB]L[/SUB] - T[SUB]R[/SUB] = T[SUB]3[/SUB] - (BP) = T[SUB]3[/SUB]/P[SUB][SUB]3[/SUB][/SUB](P[SUB]L[/SUB] - P[SUB]R[/SUB]) Because (T[SUB]L[/SUB] - T[SUB]R[/SUB])<0 Then (P[SUB]L[/SUB] - P[SUB]R[/SUB]) = -120torr. Solving for P[SUB]3[/SUB]: P[SUB]3[/SUB] =T[SUB]3[/SUB](P[SUB]L[/SUB] - P[SUB]R[/SUB])/(T[SUB]3[/SUB] - (BP)) Second Step: Let T[SUB]L[/SUB] = T[SUB]3[/SUB] and T[SUB]R[/SUB] = Unknown Temp. (T)T[SUB]L[/SUB] - T[SUB]R[/SUB] = T[SUB]3[/SUB] - T = T[SUB]3[/SUB]/P[SUB]3[/SUB](P[SUB]L[/SUB] - P[SUB]R[/SUB]) Solving for T: T = T[SUB]3[/SUB] - T[SUB]3[/SUB]/P[SUB]3[/SUB](P[SUB]L[/SUB] - P[SUB]R[/SUB]) QUESTION: Because I don't know If T>T[SUB]3[/SUB] or T<T[SUB]3[/SUB] I do not know whether (P[SUB]L[/SUB] - P[SUB]R[/SUB]) = +90torr or -90torr. How am I suppose to know? [/QUOTE]
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What is the Unknown Temp (T) in TL-TR Equation?
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