1. The problem statement, all variables and given/known data A long jumper rises 0.5 meters during the flight phase of his jump. His forward velocity is 8 ms. What is the upward velocity? 2. Relevant equations 3. The attempt at a solution Vv=Vsin[itex]\vartheta[/itex] So [itex]\vartheta[/itex] is the unkown Okay, I did a skectch to work out basic trig, with 8m/s as my H and 0.5m as my 0 using sin[itex]\vartheta[/itex]=o/h, =0.5/8 = 3 Then VV=8Sin3 = 0.38 m/s (which is wrong, but where did I go wrong??