What is the weight of the wretched Bananas in Newtons? I'm so confused

[riseofphoenix]

What is the weight of the wretched Bananas in Newtons? I'm so confused...

Ok so I tried to list out all of the stuff I was given.

Spring constant: k = 16.0 N/m
Amplitude: A = 0.2 m
Maximum speed: v = 0.434 m/s

Maximum Kinetic Energy = Maximum Spring/Potential Energy
(1/2)mv² = (1/2)kA²
(1/2)(0.434²)m = (1/2)(16)(0.2²)
0.094178m = 0.32
m = 3.39 kg

Oh wait I just realized they want it in Newtons...

mg = (3.39)(9.8) = 33.29 = 33.3

Nvm ^_^

 

[anathema]

Hi there,

First of all, it's important to clarify that weight is a measure of the force of gravity acting on an object, and it is typically measured in Newtons (N). Mass, on the other hand, is a measure of the amount of matter in an object and it is typically measured in kilograms (kg). So, the weight of an object will vary depending on its location and the strength of the gravitational field, while its mass will remain constant.

Now, let's apply this to the given information about the bananas.

The spring constant (k) and amplitude (A) are related to the maximum potential energy (U) and maximum kinetic energy (K) of the bananas as follows:

U = (1/2)kA^2
K = (1/2)mv^2

Since the maximum kinetic energy is equal to the maximum potential energy, we can set these two equations equal to each other and solve for the mass (m) of the bananas:

(1/2)mv^2 = (1/2)kA^2
m = (kA^2)/v^2

Plugging in the given values for the spring constant (k), amplitude (A), and maximum speed (v), we get:

m = (16)(0.2^2)/(0.434^2)
m = 3.39 kg

So, the mass of the bananas is approximately 3.39 kg.

However, since the question specifically asks for the weight of the bananas in Newtons, we need to multiply the mass by the acceleration due to gravity (g) to get the weight:

Weight = mg = (3.39)(9.8) = 33.22 N

Therefore, the weight of the bananas in Newtons is approximately 33.22 N.

I hope this helps to clear up your confusion. Let me know if you have any other questions. Good luck with your studies!