- #1

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I know that to solve this I need to use conservation of angular momentum, but I'm unsure what the moment of inertia is. Would it just be .5MR^2?

- Thread starter Punchlinegirl
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- #1

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I know that to solve this I need to use conservation of angular momentum, but I'm unsure what the moment of inertia is. Would it just be .5MR^2?

- #2

Galileo

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- #3

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L init= L final

Iw= Iw

mr^2 = (mr^2 + mr^2) w

I converted the linear velocity to angular velocity, v=wr

subsituting gives

85(3.5^2)(.457)= 2(85)(3.5^2) w

and dividing gives w= .229 rad/s, which isn't right.

Can someone tell me what I did wrong?

- #4

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I.e. Iw = Iw (2mr^2)w = (2mr^2)w

try using the fact that L = (m+m)vr = 2mvr along with Iw

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