Evaluating "iarray[i] < 0 && isigned" in C: Meaning Explained

[vorcil]

Homework Statement

in this statement

if (iarray < 0 && *isigned)

How do I evaluate that

the code is in c

isigned is either 0 or 1

does it mean that for each value in the array that is less than 0 AND for each value in the array that is less than isigned

or does it mean for each value in the array AND a some other statement

&& isigned (where isigned is either 0 or 1)

what does it mean?

Homework Equations

The Attempt at a Solution

 

[LCKurtz]

Homework Statement

in this statement

if (iarray < 0 && *isigned)

How do I evaluate that

the code is in c

isigned is either 0 or 1

does it mean that for each value in the array that is less than 0 AND for each value in the array that is less than isigned

or does it mean for each value in the array AND a some other statement

&& isigned (where isigned is either 0 or 1)

what does it mean?
/b]

I would think isigned must be a pointer and *isigned is the value stored at the address pointed to. So it isn't isigned which is 0 or 1, it is that value at that address that is. The && operator performs a logical AND interpreting that 1 or 0 as TRUE or FALSE.

 

[vorcil]

Cheers matey potatey

 

[NascentOxygen]

if (iarray < 0 && *isigned)

How do I evaluate that

the code is in c

isigned is either 0 or 1

does it mean that for each value in the array that is less than 0 AND for each value in the array that is less than isigned

or does it mean for each value in the array AND a some other statement

&& isigned (where isigned is either 0 or 1)

what does it mean?

This is not a looping statement. This if statement looks at only one element in the array.

The && is performed last, after iarray < 0 is evaluated. So it's equal to:
if ((iarray < 0) && *isigned)

Also, unless the first condition evaluates as true, then whatever isigned points to is not considered. So isigned need not point anywhere, not until iarray < 0 becomes true (at least as far as evaluation of this statement is concerned).

 

[DeeNos]

The statement "iarray < 0 && isigned" in C is a conditional statement that is evaluating two conditions using the logical AND operator (&&). The first condition is "iarray < 0", which checks if the value at index i in the array iarray is less than 0. The second condition is "*isigned", which checks if the value of the variable isigned is equal to 1 (true).

In this statement, the code is checking if both conditions are true. If the first condition is true (iarray < 0), then the second condition is also checked. If both conditions are true, then the code will proceed to execute the following code block. If either of the conditions is false, then the code will not execute the following code block.

To evaluate this statement, you would need to provide values for the variables iarray and isigned. For example, if iarray = [1, -2, 3, -4] and isigned = 1, then the first condition (iarray < 0) would evaluate to true for the values at indices 1 and 3, while the second condition (*isigned) would evaluate to true for the value 1. Therefore, the code block following this statement would be executed for the values at indices 1 and 3 in the array iarray.

In summary, the statement "iarray < 0 && isigned" in C is evaluating if both the value at index i in the array iarray is less than 0 and if the value of the variable isigned is equal to 1. It does not mean for each value in the array AND a some other statement, but rather for each value in the array that satisfies both conditions.