1. Aug 26, 2012 #1

   aaaa202

   

   Consider the equation on the attached picture. What mathematical identity for differential calculus (which I assume is used) is used to go from the LHS to the RHS? I tried invoking the product rule but couldn't get anywhere.

    

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   aaaa202, Aug 26, 2012
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3. Aug 26, 2012 #2

   TSny

   

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   You're on the right track. Apply the product rule to the first term on the RHS and show that the entire RHS reduces to the LHS.

    

   TSny, Aug 26, 2012
4. Aug 26, 2012 #3

   TSny

   

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   Or, if you really want to go from the LHS to the RHS then use ([itex]\frac{dA}{dt}[/itex][itex])\cdot[/itex]B = [itex]\frac{d}{dt}[/itex](A[itex]\cdot[/itex]B) - A[itex]\cdot[/itex][itex]\frac{dB}{dt}[/itex] which is just the product rule rearranged.

    

   TSny, Aug 26, 2012

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