For a flat road, where a car is turning, the max speed can by found by:(adsbygoogle = window.adsbygoogle || []).push({});

Fc = Ff

mv^2/r = uFg = umg

v = sqrt(rug)

For a banked road with angle T, the max speed (i think i did this wrong)

mv^2/r = Fnsin(T) + Ffcos(T)

mv^2/r = mg*sin(T) + umg*cos(T)

v = sqrt(rg(sin(T) + ucos(T))

but sin(T) + ucos(T) can be < 1 for low u's! this doesnt make sense.. in other words its saying that in some cases, driving on a bank results in a lower max v than driving on a flat road..

what did i do wrong?

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# What is wrong with my derivation of max speed on inclined curves?

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