- #1
michaelw
- 80
- 0
For a flat road, where a car is turning, the max speed can by found by:
Fc = Ff
mv^2/r = uFg = umg
v = sqrt(rug)
For a banked road with angle T, the max speed (i think i did this wrong)
mv^2/r = Fnsin(T) + Ffcos(T)
mv^2/r = mg*sin(T) + umg*cos(T)
v = sqrt(rg(sin(T) + ucos(T))
but sin(T) + ucos(T) can be < 1 for low u's! this doesn't make sense.. in other words its saying that in some cases, driving on a bank results in a lower max v than driving on a flat road..
what did i do wrong?
Fc = Ff
mv^2/r = uFg = umg
v = sqrt(rug)
For a banked road with angle T, the max speed (i think i did this wrong)
mv^2/r = Fnsin(T) + Ffcos(T)
mv^2/r = mg*sin(T) + umg*cos(T)
v = sqrt(rg(sin(T) + ucos(T))
but sin(T) + ucos(T) can be < 1 for low u's! this doesn't make sense.. in other words its saying that in some cases, driving on a bank results in a lower max v than driving on a flat road..
what did i do wrong?