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Thanks

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- Thread starter Raza
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Thanks

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Doc Al

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"Radial" just means "along the radius" or towards the center (also called *centripetal*). Realize that velocity--a vector--can change (accelerate) either by changing magnitude or direction or both. For something going in a circle you can express the acceleration as having a tangential component (changing *magnitude*, tangent to the circle) and a radial component (changing *direction*, towards the center).

The expression [tex]\frac{v^2}{r}[/tex] gives the radial component of acceleration for something going in a circle. To see where such a formula comes from, look here: http://hyperphysics.phy-astr.gsu.edu/hbase/cf.html#cf2"

The expression [tex]\frac{v^2}{r}[/tex] gives the radial component of acceleration for something going in a circle. To see where such a formula comes from, look here: http://hyperphysics.phy-astr.gsu.edu/hbase/cf.html#cf2"

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arildno

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Well, visualize a circle with a radius, then.

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haha funny.

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Please respond

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Doc Al

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Make sense?

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Are you familiar with what a vector is?

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yes, scalar is something with no directions (ex.speed) and vector is something with directions (ex.velocity)

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Are you familiar with what acceleration is, in terms of vectors?

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no, I am not familiar with what acceleration is, in terms of vectors.

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The acceleration manifests itself in two possible forms. The first form is an actual change in the magnitude of the velocity (think of the velocity vector as increasing or decreasing in length, but pointing in the same direction).

The other possible acceleration occurs when the velocity vector maintains its magnitude but changes its direction. This is consistent with our notion of acceleration because there is a still change in velocity (this time the change is direction, and not magnitude).

When you are moving in a circle with constant tangential velocity, the direction of the velocity vector always changes as the particle moves but maintains its magnitude |v|. So your equation is a=|V|^2/R.

The direction of this acceleration will always point towards the center of the circle.

I would recomend you grab a physics book (Sears and Zemanski, or halliday and resnik) and read the first two chapters. It will give you a sufficient answer.

The other possible acceleration occurs when the velocity vector maintains its magnitude but changes its direction. This is consistent with our notion of acceleration because there is a still change in velocity (this time the change is direction, and not magnitude).

When you are moving in a circle with constant tangential velocity, the direction of the velocity vector always changes as the particle moves but maintains its magnitude |v|. So your equation is a=|V|^2/R.

The direction of this acceleration will always point towards the center of the circle.

I would recomend you grab a physics book (Sears and Zemanski, or halliday and resnik) and read the first two chapters. It will give you a sufficient answer.

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