What should its speed be relative to the ground?

In summary: PA=205 km/hvAG=50 km/hvPG=255 km/hIn summary, the pilot of an aircraft wishes to fly due west in a 50.0 km/h wind blowing toward the south. The speed of the aircraft in the absence of a wind is 255 km/h.
  • #1
AHuds0n
3
0
Relative Motion - I need help on it and more help

I need help on Relative Motion. I'm about to literally pull my hair out if I don't understand how to do this. I would very appreciate it if someone could help me out with this one problem and I probably could do the other by myself.

The pilot of an aircraft wishes to fly due west in a 50.0 km/h wind blowing toward the south. The speed of the aircraft in the absence of a wind is 205 km/h.

a. In what direction should the aircraft head?
b. What should its speed be relative to the ground?


I've spent at least 3 hours on this homework.

This is what I started out doing:

I sketched a picture of the aircraft's and wind's direction.
The plane was going west 205 km/h and the 50 km/h wind was going south. And I tried finding the displacement using the pythagorean theorem but the answer was wrong. And I divided 205 km/h over 50 km/h and used tan-1 with the anwer to get the direction but it was wrong.


I'm not even sure if I went about the problem right.
 
Last edited:
Physics news on Phys.org
  • #2
A useful convention to adopt for these relative motion problems would be to call the velocity of the plane with respect to the air vPA. That is, the first subscript indicates what is moving and the second subscript indicates with respect to what reference frame the body is moving. So, you are given the magnitude of this vector: vPA=205 km/h. Since you don't know the direction, characterize it by an angle θ and write out the vector in component form.

You are also given the velocity of the air. This should be interpreted as the velocity of the velocity of the air with respect to the ground, and I would call it vAG. You are further told that the plane is to head due west, which means that the velocity of the plane with respect to the ground is to point in that direction. Call this velocity vPG.

Why use this notation? Because it makes relative velocity problems a piece of cake. The correct way to write the vector sum is such that the subscripts line up as follows:

vPG=vPA+vAG.

That is, the outer subscripts on the right hand side ("P" and "G") have to match the subscripts on the left hand side, and the inner subscripts in the right hand side ("A" and "A") have to be the same.

Can you take it from there?
 
  • #3
I think I can.

Thankyou b/c I was so lost.
 
  • #4
So I add 205 km/h and 50 km/h and get 255 km/h?

And 255 km/h is the Vpg?

What do I do with the Vpg?

I'm more lost than I ever was.
 
  • #5
AHuds0n said:
So I add 205 km/h and 50 km/h and get 255 km/h?

And 255 km/h is the Vpg?

No! These are vectors, so you have to add them as vectors.

Write down a vector to represent each velocity. Write it down in i, j component form.
 

1. What is meant by "speed relative to the ground"?

When we talk about an object's speed relative to the ground, we are referring to its velocity in relation to the Earth's surface. In other words, it is the speed at which the object is moving with respect to the ground.

2. How is an object's speed relative to the ground calculated?

An object's speed relative to the ground can be calculated by measuring its displacement (change in position) over time. The formula for speed is distance divided by time, so to find the speed relative to the ground, we would divide the object's displacement by the time it took to cover that distance.

3. What factors can affect an object's speed relative to the ground?

The speed of an object relative to the ground can be affected by several factors, including the object's initial velocity, any forces acting upon it (such as gravity or air resistance), and changes in the surface it is moving on (e.g. going uphill or downhill).

4. Can an object have different speeds relative to the ground at different points in time?

Yes, an object's speed relative to the ground can change over time. This can occur if the object is accelerating or decelerating, or if external factors change (such as the incline of the ground or the presence of a strong headwind).

5. How does an object's speed relative to the ground differ from its speed relative to another object?

An object's speed relative to the ground is specifically referring to its velocity in relation to the Earth's surface. On the other hand, an object's speed relative to another object would be the velocity at which they are moving in relation to each other. This could be different if the two objects are moving in the same direction or against each other, for example.

Similar threads

  • Introductory Physics Homework Help
Replies
4
Views
774
  • Introductory Physics Homework Help
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
865
  • Introductory Physics Homework Help
Replies
14
Views
6K
  • Introductory Physics Homework Help
Replies
11
Views
1K
  • Introductory Physics Homework Help
Replies
5
Views
4K
  • Introductory Physics Homework Help
Replies
10
Views
3K
  • Introductory Physics Homework Help
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
5
Views
941
  • Introductory Physics Homework Help
Replies
21
Views
177
Back
Top