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I am having some trouble with discerning whether current (electrons flowing through the Tungsten), or the energy transfer as described by the poynting vector, is responsible for lighting the lightbulb.
The current flowing through the filament heats the tungsten to incandescence. Light is given off by things heated to incandescence. Every time a photon leaves the filament, the energy of the filament is reduced. During normal operation, the rate of heating (I^2R) is equal to the rate that energy leaves the filament as photons -- i.e. steady state is achieved, and the temperature reaches a constant value.I am having some trouble with discerning whether current (electrons flowing through the Tungsten), or the energy transfer as described by the poynting vector, is responsible for lighting the lightbulb.
They are essentially the same. The power density throughout the bulk of the filament is given by the current density (squared) and the resistivity. This quantity will be equal to the Poynting flux across the surface of the filament.I am having some trouble with discerning whether current (electrons flowing through the Tungsten), or the energy transfer as described by the poynting vector, is responsible for lighting the lightbulb.
When you say "energy transfer" are you asking about the energy transfer from the field at one point to the field at another point or are you asking about the energy transfer from the field at one point to the matter at the same point? The Poynting flux is the first, and the joule heating is the second.is it that the cross product of the two fields, ExB, is responsible for the energy transfer
Don't you think that you may be overdoing it. Sometimes, P=I2R is sufficient and you don't need to analyze it with Maxwell's Equations.I am having some trouble with discerning whether current (electrons flowing through the Tungsten), or the energy transfer as described by the poynting vector, is responsible for lighting the lightbulb.
Wow, why are you making this more complicated than it is?Hi Dale,
Thank you. Although they may have an equal value, is it that the cross product of the two fields, ExB, is responsible for the energy transfer, with the source of this EM wave being related to the E field induced by the current? I simply want to know what the source of the energy is, that we see lost as the heat and light. Is it the EM wave generated by the two fields, or simply electron flow. A bit confusing to me, and thank you very much for taking the time to answer.