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- Thread starter touqra
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P.S.

Quantum objects aren't very easy to manipulate, I think. Especially if you want to keep them in their original state.

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It depends. If they are tied to some nucleus, each of their energy levels splits up and one of them (irrelevant which one, they're both the same) will go to higher energy state.touqra said:

If they are, let's say, free and you try to push them closer (I think something like that happens in white dwarfs or neutron stars) you will reach certain limit above which you cannot bring them any closer due to the pauli exclusion principle. You can imagine (at least that's how I do it) that each fermion establishes a "zone" around himself in which other fermions are not allowed to enter which is not effect of any force, but only consequence of their indistinguishability (hope I spelled this correctly .

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If I may elaborate on this for the OP...You can imagine (at least that's how I do it) that each fermion establishes a "zone" around himself in which other fermions are not allowed to enter which is not effect of any force,

Take a simple two fermion state:

Using bra-ket formalism,

[tex] \mid\psi_1, \psi_2>= \frac{1}{\sqrt2} (\mid\psi_1> \mid\psi_2> - \mid\psi_2> \mid\psi_1> ) [/tex]

we clearly see that we can't have two fermions in the same state ( [itex] \psi_1=\psi_2[/itex] ).

But, since you (touqra) are interested in finding fermions in space we should use take a product of a coordinate x (1D, for simplicity) with the state (aka wavefunction):

[tex]\Psi(x_1, x_2)=\psi(x_1) \psi(x_2) - \psi(x_2) \psi(x_1) [/tex]

Now, the probability of finding a system in some place is the square of the wavefunction. The probability of finding the two fermions will be decrease as the distance between them decreases, but will only be zero when [itex]x_1=x_2[/itex]

My point is that there doesn't exist a minimum distance between two fermions in the same state below which we will never find them, that is the "zone" that Igor_S mentions isn't clearly defined.

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