I was trying to figure out the number of electrons and protons in 1.00 gram of Hydrogen.
What answer did you get and how did you arrive there?
By the way: the two numbers should be the same.
The easy answer would be to use the concept of a mole as well as the known atom weight of hydrogen to deduce that 1 gram of hydron should have about 5.97 X 10^23 atoms. Hydrogen only has 1 proton thus the number of protons. How many electrons a hydrogen atom contains would depend on what state it is in. Hydrogen at its gas, liquid and I believe its should have one electron. Thus the number of atoms, electrons and protons would be the same.
Hydrogen in the plasma state would have no electrons.
the formula to figure out the number of atoms in 1 gm of hydron is
mass of sample, in this case 1 gram divided by the atomic weight of hydrogen which is 1.00794 times the avogadro number(N) which is 6.02213x10^23. So it would be (1 / 1.11794)X 6.02213x10^23 = 5.97x10^23.
The electrons are still there, but they are dissociated from the protons. The plasma itself is usually electrically neutral.
6.022 x 10^23 atoms of hydrogens weigh 1 gram (1.008g)...1 mole of hydrogen. 1 atom of hydrogen has 1 electron, and 1 proton. Therefore 1 gram of hydrogen would have 6.022 x 10^23 electrons and 6.022 x 10^23 protons.
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