Whats the inverse of sec^2x?

and how would i go about working out the inverses of trig functions if i didnt already know them?
 
First off: [tex]\sec^2\theta=1+\tan^2\theta[/tex]
=

[tex]\sec\theta={\sqrt{1 +\tan^2\theta}}[/tex]
 
Last edited:

uart

Science Advisor
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bill nye scienceguy! said:
and how would i go about working out the inverses of trig functions if i didnt already know them?
Vague question but I suspect you mean do the following.

x = 1 / cos^2(y)

sqrt(x) = 1/cos(y)

1/sqrt(x) = cos(y)

y = arccos(1/sqrt(x))

Now that's only half the solution, the most important part is working out the domain and range for which this inverse makes sense.
 

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