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Whats the inverse of sec^2x?

  1. Feb 6, 2006 #1
    and how would i go about working out the inverses of trig functions if i didnt already know them?
  2. jcsd
  3. Feb 6, 2006 #2
    First off: [tex]\sec^2\theta=1+\tan^2\theta[/tex]

    [tex]\sec\theta={\sqrt{1 +\tan^2\theta}}[/tex]
    Last edited: Feb 6, 2006
  4. Feb 6, 2006 #3


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    Vague question but I suspect you mean do the following.

    x = 1 / cos^2(y)

    sqrt(x) = 1/cos(y)

    1/sqrt(x) = cos(y)

    y = arccos(1/sqrt(x))

    Now that's only half the solution, the most important part is working out the domain and range for which this inverse makes sense.
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