[tex]sin(z)=2[/tex](adsbygoogle = window.adsbygoogle || []).push({});

[tex]e^{iz}-e^{-iz} = 4i[/tex]

[tex]e^{2iz}-4ie^{iz} = 1[/tex]

[tex]iz \ln (e^{iz}-4i) = 0[/tex]

[tex] z=0[/tex]

when solving it by

[tex]w = e^{iz}[/tex]

[tex]w^2-4wi-1 = 0[/tex]

i get one more solution, why is the first way not as good as the second way?

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# Homework Help: Whats wrong here?

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