WHat's wrong in my argument?

  • Thread starter mansi
  • Start date
  • #1
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I was asked to prove, every punctured open set in R^2 is path connected.

My argument : take points x and y. let z be the point we've taken off from U (open).
if x, y,z do not pass through a staright line, we have a segment between a and y.
Now if the 3, i.e. x,y,z lie on a straight line...then pick another point ,say p, not lying on the staright line.
we have segments joining x and p and p and y. hence, we've found a path between x and y ,as required.

apparently, this is wrong...my prof told me not bring in straight lines anywhere! any hints?? thanks!
 

Answers and Replies

  • #2
454
1
What if your set is not convex?
 
  • #3
NateTG
Science Advisor
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Can you show that there's a 'path' that circles the puncture?
 

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