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When do vcm=rw and a=gsintheta/(1+I/(MR)^2) apply?
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[QUOTE="fangrz, post: 5003348, member: 542277"] I see now. The equation vcm=rw would not apply if the ball was moving but not having rotational motion. This is how I set up the equation: Consider an object rolling down a inclined plane. Torque=RFs R=radius, Fs=static friction Also, Torque=I*alpha I=moment of inertia alpha=angular acceleration This leads to Torque = I*alpha=I*(a/R) where a=acceleration centripetal Setting RFs=I*(a/R) gives us Fs=(I*a)/R^2 So we have Fnet=ma=gravitational force down the incline plane-force of friction which is=(mgsintheta)-(Ia)/R^2 Solving for a and manipulating the equation gives that a=(gsintheta)/(1+(I*alpha)/MR^2) [/QUOTE]
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Introductory Physics Homework Help
When do vcm=rw and a=gsintheta/(1+I/(MR)^2) apply?
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