- #1
laurenyntema
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1. A model rocket with a mass of 4.3kg is launched straight up at a speed of 65m/s. Kinetic energy when it takes off is 9083.75 J. Total energy when it takes off is also 9083.75J. When the rocket reaches its maximum height, what is its kinetic energy?
2. KE(kinetic energy)=1/2MV^2
3. KE= 1/2(4.3)(65^2)
KE=1/2(4.3)(4225)
KE=1/2(18167.5)
KE=9083.75... not sure where to go from here...
2. KE(kinetic energy)=1/2MV^2
3. KE= 1/2(4.3)(65^2)
KE=1/2(4.3)(4225)
KE=1/2(18167.5)
KE=9083.75... not sure where to go from here...