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When the Sun is directly overhead, a hawk dives toward the ground with a constant vel

  1. Mar 7, 2012 #1
    When the Sun is directly overhead, a hawk dives toward the ground with a constant velocity of 4.15 m/s at 54.5° below the horizontal. Calculate the speed of her shadow on the level ground.1. The problem statement, all variables and given/known data



    2. Relevant equations

    vxi=vicosθ vyi=visinθ (i think)

    3. The attempt at a solution
    360-54.5=305.5
    4.15cos305.5=-2.99i
    4.15sin305.5=-2.88j
    then get the modulus of the vector for the speed. Gave me 4.155
    Its wrong though?
    Help?
    Tell me where I went wrong and where to begin
    Thanks
     
    Last edited: Mar 7, 2012
  2. jcsd
  3. Mar 7, 2012 #2
    Re: When the Sun is directly overhead, a hawk dives toward the ground with a constant

    Where is the original question?
     
  4. Mar 7, 2012 #3
    Re: When the Sun is directly overhead, a hawk dives toward the ground with a constant

    oops sorry!
     
  5. Mar 7, 2012 #4
    Re: When the Sun is directly overhead, a hawk dives toward the ground with a constant

    Is your calculator in radians or degrees?
     
  6. Mar 7, 2012 #5
    Re: When the Sun is directly overhead, a hawk dives toward the ground with a constant

    it was on radians! Thank you! I got the right answer!
     
  7. Mar 7, 2012 #6
    Re: When the Sun is directly overhead, a hawk dives toward the ground with a constant

    Careful Careful... Make sure you never forget this during a test!
     
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