When the Sun is directly overhead, a hawk dives toward the ground with a constant vel

1. Mar 7, 2012

When the Sun is directly overhead, a hawk dives toward the ground with a constant velocity of 4.15 m/s at 54.5° below the horizontal. Calculate the speed of her shadow on the level ground.1. The problem statement, all variables and given/known data

2. Relevant equations

vxi=vicosθ vyi=visinθ (i think)

3. The attempt at a solution
360-54.5=305.5
4.15cos305.5=-2.99i
4.15sin305.5=-2.88j
then get the modulus of the vector for the speed. Gave me 4.155
Its wrong though?
Help?
Tell me where I went wrong and where to begin
Thanks

Last edited: Mar 7, 2012
2. Mar 7, 2012

Ericv_91

Re: When the Sun is directly overhead, a hawk dives toward the ground with a constant

Where is the original question?

3. Mar 7, 2012

Re: When the Sun is directly overhead, a hawk dives toward the ground with a constant

oops sorry!

4. Mar 7, 2012

Ericv_91

Re: When the Sun is directly overhead, a hawk dives toward the ground with a constant

5. Mar 7, 2012

Re: When the Sun is directly overhead, a hawk dives toward the ground with a constant