When you double your distance from a sound source

  • Thread starter Dx
  • Start date
  • #1
Dx
This cant be right.

I missed this test question here.

You shout at a cliff and hear the echo in 4s. the temp is 0 degrees C. How far away is the cliff?

I think the answers were a)662 b) 680 c) 1320 d)1760

I chose c because

t=d/s or d=t*s

now, i substitued d = 4s * 331m/s = 1324

why did i miss this? I am pretty sure the formula and math is
right?


also one more question



when you double your distance from a sound source radiating in all directoins. what happens to the intensity of the sound? is reduces to 1/2 its orginal value.

Thats what i said unless its 1/4. what is the right answer.

Dx :wink:
 
Last edited by a moderator:

Answers and Replies

  • #2
1,036
1
a)
You computed:
d = 4s * 331m/s = 1324

That was exactly correct -- for the distance from you to the cliff and back. D is twice the distance from you to the cliff. So, the correct answer is a)662 m.

b)
Sound intensity varies inversely with the square of the distance, so the correct answer to the second question was 1/4.
 
  • #3
Dx
thanks gnome!
 

Related Threads on When you double your distance from a sound source

Replies
0
Views
3K
Replies
4
Views
6K
Replies
1
Views
908
Replies
2
Views
10K
Replies
2
Views
3K
  • Last Post
Replies
11
Views
2K
Replies
1
Views
3K
Replies
8
Views
24K
Replies
6
Views
3K
Replies
5
Views
2K
Top