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Homework Help: Where did I go wrong?

  1. Feb 7, 2006 #1
    Question:

    Find the derivative of the function: https://webwork2.math.ohio-state.edu/courses/math151wi06sm/tmp/png/Hmwk4/126384/kopko.4-prob16image1.png [Broken]

    My answer:
    9ebc755a.jpg

    Can please someone tell me where I messed up.

    Edit: i used that chain rule or something like that

    So first I changed the equation into [5x+(3x+sqrt(2x))^.5]^.5

    then I found the first derivative, so it was .5[5x+(3x+sqrt(2x))^.5]^-.5

    Next I did it for 5x and the 1/2 power-> 5+.5(3x+sqrt(2x))^-.5

    I did the same for the following 2 steps. I hope that helps.
     
    Last edited by a moderator: May 2, 2017
  2. jcsd
  3. Feb 7, 2006 #2

    Pengwuino

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    Gold Member

    If you can show us what you did step-by-step (i know, that's hard with square roots unfortunately), we can help you determine where you went wrong.
     
  4. Feb 7, 2006 #3

    krab

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    Science Advisor

    your brackets are messed up. The last (third) bracketed factor does not multiply everything, just the part that starts with 3x.
     
  5. Feb 7, 2006 #4
    which brackets?
     
  6. Feb 8, 2006 #5
    sorry to bump the topic

    but could someone please explain what bracket krab means.
     
  7. Feb 8, 2006 #6

    VietDao29

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    Homework Helper

    It may be quite impossible for us to guess your approach, and thus, we don't know where you went wrong. Now, may I ask you to post step by step solution, so that we can check it for you. :)
    You don't have to LaTeX, or use MS Equation Editor, just jot down your steps in a paper, then use a scanner and post it here. :)
    You can also learn how to LaTeX. There are three PDFs on the first post of that thread. The thread is a sticky in the Math & Science Tutorials board.
     
  8. Feb 8, 2006 #7
    He means that the "inner derivatives" do not multiply the entire expression. The last bracket - which by the way is not correct - is not supposed to be multiplied with the entire expression. It has to be inside the second bracket.


    EDIT: Explained better hopefully, without giving out too much of the solution.
     
    Last edited: Feb 8, 2006
  9. Feb 8, 2006 #8

    NateTG

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    Homework Helper

    What is meant is that the grouping (where the parentheses are) is incorrect.

    Hint:
    [tex]\frac{d}{dx}\sqrt{3x+\sqrt{2x}} \neq \left(3+\frac{.5}{\sqrt{2x}}\right)*2[/tex]
     
  10. Feb 8, 2006 #9

    krab

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    Science Advisor

    The 3rd big bracketed factor has to be INSIDE the bracket just ahead of it. IOW, it does not multiply the 5+ of the second big bracketed factor.
     
  11. Feb 8, 2006 #10
    [tex] \frac{1}{2}(3x+(2x)^{1/2})^{1/2})^{-1/2}*(5+\frac{1}{2}(3x+(2x)^{1/2})^{-1/2}*(3+\frac{1}{2}(2x)^{-1/2}*2))[/tex]


    =

    [tex]

    \frac{20*\sqrt{x}*\sqrt{\sqrt{x}*(3*\sqrt{x}+\sqrt{2})}+6*\sqrt{x}+\sqrt{2}}{8*\sqrt{x}*\sqrt{\sqrt{x}*(3*\sqrt{x}+\sqrt{2})}*\sqrt{\sqrt{\sqrt{x}*(3*\sqrt{x}+\sqrt{2})}+5*x}}



    [/tex]
     
    Last edited: Feb 8, 2006
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