# Where does the energy go?

1. Feb 26, 2007

### disregardthat

Energy cannot disappear as we all know, but then I wonder: If we put force to an object and make it go at a high speed, and then put force to it to make it go back to a halt. Where did the energy go? We used force at acceleration and deceleration, but we only got a change in position for the object. Surely the energy is not lost. (of course we cannot retrieve the energy by forcing the object back in its initial position)

2. Feb 26, 2007

### cristo

Staff Emeritus
What do you mean by this? Remember that acceleration is a vector quantity, and also that v=0 does not imply a=0, and so in your case you have a change in acceleration.

3. Feb 26, 2007

### haiha

When you make something to go at a high speed, you give it some kinetic energy. When you try to stop it, the energy normally turns into heat, another type of energy.

4. Feb 26, 2007

### disregardthat

cristo, what I meant was the we accelerate the object and then decelerate it to a complete halt, so it has no change in velocity at the end. A change in acceleration is a good explanation of transformation of energy to me, if we only accelerated it once, but then decelerating it (accelerating) til stop again, I don't see where the energy has gone.

haiha: So it must turn to some sort of energy, for example heat you say?

5. Feb 26, 2007

### Staff: Mentor

Accelerating an object can add KE or remove KE, depending upon the direction of the acceleration compared to the velocity of the object. (It can even leave the KE unchanged, if the accelerating force remains perpendicular to the velocity--like something twirled in a circle.)

Of course, if you add or remove KE, that energy must come (or go) from somewhere.

6. Feb 26, 2007

### HallsofIvy

You did work on the object when accelerating it. The object did work on you when decelerating it.

Think of it this way: compress a spring, doing work to store potential energy in the spring. Now use that spring to accelerate your object.

Quickly run around in front of the object, place your spring in front of it and use the spring to slow it. Ignoring resistance or any kind of friction, the kinetic energy in the object will be exactly enough to compress the spring back to where it was before. If you don't like the idea of "running around in front of the object", imagine two different but identical springs. Same thing happens. Net result, you did work to compress a spring initially, and now you are back in that same situation. No energy change.

7. Feb 26, 2007

### arunma

The answer here is that the kinetic energy you put into the object was later transformed either into potential energy somewhere else, or into heat. For example, if you use a spring to stop the object, the kinetic energy from the formerly moving object will be transformed into spring kinetic energy. Or if you stop an object by friction (or some other non-conservative force), then the kinetic energy will be lost to friction. I could give slightly different answers based on the mechanism used to stop the object, but this is the basic idea.

8. Feb 26, 2007

### disregardthat

So it's actually just a wrong perspective of seeing it from the beginning. I see it now. Does momentum count as energy, or more particulary: Is momentum kinetic energy?

9. Feb 26, 2007

### KingNothing

Yes and no. They are not the same thing. However, you may notice that momentum "p" is the derivative of kinetic energy with respect to velocity:

$$$\begin{array}{l} E_k = {\textstyle{1 \over 2}}mv^2 \\ p = mv \\ \end{array}$$$

Last edited: Feb 26, 2007
10. Feb 26, 2007

### disregardthat

I see, thanks.

11. Feb 26, 2007

### Staff: Mentor

Also, if you give something (like a car) a push, then run around to the other side of it and stop it, you'll expend roughly the same amount of energy stopping it as you did in starting it moving, since your muscles aren't springs.

In Hurkyl's example with the springs, the end result looks exactly like a mirror image of the initial setup and you're back to zero as if nothing had happened. In an example with a person, you've converted a lot of chemical energy to heat.

And to meet the two in the middle, if you use the car's engines to proved the push then the brakes to provide the stopping, it works exactly the same from an energy standpoint as if all the engine's initial energy input had been turned directly to heat.

Last edited: Feb 26, 2007