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Where in the sky is the sun?

  1. Nov 1, 2011 #1

    Duplex

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    Sunlight takes eight minutes to reach Earth. Meanwhile the sun and Earth have moved/rotated.

    Suppose that the sun emitted two types of light, the 8-minute light and a spooky “zero-time light”. Where in the sky would we see/measure the second spooky sun - the real position of the sun?

    The approximate angle or distance in sun diameters?
     
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  3. Nov 1, 2011 #2
    Well that depends on the time of year, and probably slightly on atmospheric condition (refraction is dependent on moisture and angle).

    There are equations easily available online which can calculate the position of the sun. You would simply have to find the difference in angle between a point now, and a point 8 minutes from now.
     
  4. Nov 1, 2011 #3

    russ_watters

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    That's not what the question asked....

    Duplex, given that the earth rotates in 24 hours, how far (in angle) does it travel in 8 min? That is not a difficult calculation...
     
  5. Nov 1, 2011 #4
    I'm sorry but I don't see a huge distinction between our two answers. The earth rotates every 24 hours but the elevation angle changes depending on the time of the year. In the winter the change in elevation angle over a full day is much less than in the summer, and peaks at solar noon.

    In other words, there are two angles to account for, the azimuthal and elevation angles. simply dividing 360 degrees by 24 hours and using that ratio with 8 minutes will not suffice.
     
  6. Nov 1, 2011 #5

    russ_watters

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    Sorry, I read the first 3/4 and missed the last sentence!

    However, the OP just said angle, not elevation angle. So I wouldnt go more complicated than a time ratio calc.
     
  7. Nov 1, 2011 #6
    It's okay :smile:. I might be getting a little defensive today too. You're not the first PF Mentor to give me a hard time today haha.
     
  8. Nov 1, 2011 #7

    russ_watters

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    Er..sorry, late edit
     
  9. Nov 1, 2011 #8

    Duplex

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    Could it be a difference if the Earth rotates or the sun revolves around the Earth? A sort of three-body problem?

    1. The sun is stationary in the sky and sends its parallel light as a laser beam towards the Earth.
    Eight minutes before sunrise, it emits light that reaches me at sunrise. As the sun and solar direction coincide, the 8-minute light and the zero-time light coincide, i.e. the sun is really where I see it.

    No matter the angle where I see the sun in the sky, there is only one sun in which the 8-minute position and the real position are identical.

    2. The sun revolves around Earth. The medieval approach.
    Don’t we then "see" two suns, the eight minutes old position and the sun's actual position?

    I guess this question is somewhat simple, maybe I'm suffering from brain-fag but it was a baffling spin-off from a FTL discussion among some friends a year ago. If we had a measurement instrument for a hypothetical FTL-effect where would we find the sun in the sky.
     
  10. Nov 1, 2011 #9
    I don't understand what you are saying.

    The sun's position in the sky is always moving relative to an observer on Earth. That's about all I can say.
     
  11. Nov 1, 2011 #10

    A.T.

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    No, you will see two suns. The 8-minute light will be subject to aberration:
    http://en.wikipedia.org/wiki/Aberration_of_light
    For the zero-time light aberration is zero.

    Yes, here we also see two suns. But in this frame we attribute it to delayed signal from an outdated source position for the 8-minute light.
     
  12. Nov 1, 2011 #11
    There is 360 degrees in a full circle. There is 1440 minutes in a day. Work it out.
     
  13. Nov 1, 2011 #12

    sophiecentaur

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    This thread has me confused. What can you possibly be implying when you say that you can see "two suns"? It is either a wind up (never on PF, I'm sure :confused:) or a novel / alternative attempt to consider what is going on. But there is no paradox involved.

    The only light that will reach Earth has taken 8 minutes to get here - by which time the Earth has rotated 360X 60/1440 degrees since it was emitted. How can you suggest that you could 'see' the light earlier than that? You could draw a diagram with lines on it to show two paths, possibly, but the one path would represent an impossible journey for the light (the no-time delay path doesn't exist)
     
  14. Nov 1, 2011 #13

    Drakkith

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    I'm not sure why this is so complicated. IF there was this "FTL" light from the sun that reached you, you would see 2 suns, one of them, the FTL light, would be slightly ahead of the normal one. Since FTL doesn't exist this does not happen. To see where the sun "really" is you would predict its location based on the knowledge of how far the Earth is from the Sun and how fast light travels.
     
  15. Nov 1, 2011 #14

    sophiecentaur

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    Doesn't all this boil down to frames of reference?
    People are trying to introduce a problem where there isn't one.
     
  16. Nov 1, 2011 #15
    Blimey, here's the simple answer:
    The zero-delay sun will be where the sun you see is in 8 minutes time.
    Which is probably about a four sun diameters.

    The speed of the sun through the galaxy etc doesn't make a difference as the earth goes the same speed.
     
  17. Nov 1, 2011 #16

    Duplex

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    Thank you guys.
    I have considered all your answers, and I can not find anything but the problem arises if I look at the sun's apparent journey across the sky as equivalent to Earth's rotation with a stationary sun.

    I think there is a difference. In the first case we have two suns, the illusory one we see with eight-minute delay with our eyes and the real position is slightly ahead in the direction of travel. It's like a jet in a perpendicular motion, where the light reaches us first and then the slow sound is lagging behind.

    In the second case, our 24 hour rotation, we see the sun in its real position, where the sunlight that reaches us consists of two components: the old 8-minute light and a hypothetical fresh FTL-light.

    I hope my basic problem has been to understand how my academic friends (no physicists) who discussed this subject at a party could have such different views.

    Now, it is far past midnight here and it's time to sleep…
     
  18. Nov 2, 2011 #17

    A.T.

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    So you guys seriously think that the visible position of the sun is about 2° off the actual direction to the sun, because the Earth rotates 360° per 24h?

    What if I stand on the north pole (during the summer there)? Same offset? What if I stand on the north pole and start spinning faster than the Earth? Will the offset increase?
     
  19. Nov 2, 2011 #18

    sophiecentaur

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    Wherever you stand, the azimuth error will be the same because the Earth is rigid and rotates at the same rate around its axis all over the surface (forget tides). The actual position in the sky will not be shifted by the same amount but that is only a detail of geometry (not time and c) and doesn't really help in the philosophy of this discussion.
     
  20. Nov 2, 2011 #19

    A.T.

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    The only thing that causes an offset between the visible and real direction, is the component of relative velocity (between source & detector) that is perpendicular to the real direction. The dominating effect here is the orbital velocity of the Earth, but the offset from it is very small probably not visible with the naked eye. The rotation of the Earth plays a tiny role, and that only if you are not one of the poles, so you have some tangential velocity from that rotation.
     
    Last edited: Nov 2, 2011
  21. Nov 2, 2011 #20

    A.T.

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    - What exactly is "azimuth error" ?
    - What is its value?
    - If I don't stand still on the pole, but start to rotate will the "azimuth error" be different?
     
    Last edited: Nov 2, 2011
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