two charges of 1.5X10^-6 c and 3.0X10^-6 c are 0.2 m apart. Where is the electric field between them equal to zero?(adsbygoogle = window.adsbygoogle || []).push({});

heres what i got....

the electric field will be 0 when the field strength of the first charge minus the field strength of the second charge equals 0.

therefore,

q(1)-----x------P-------(0.2 - x)-------q(2)

where...

P is where the electric field equals 0

q(1) is the first charge

q(2) is the second charge

x is the distance (in metres) from the charge

[ kq(1) / (x)^2 ] - [ kq(2)/ ((0.2-x)^2) ] = 0

from here,

i cancel out the k's

find the common denominator and cancel it out once my numerator is expanded

try and use the quadratic equation to solve for x. however, when i try to solve for x i get a complex number...what am i doing wrong? the book says the answer is 0.08m (approx.) if you know a faster and much easier way, please do tell...thanks a bunch...

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# Homework Help: Where is the electric field is zero?

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