Ux = 47.04
Uy = 19.6
Vx = 47.04
Vy = 19.6 - gt
Ax = 0
Ay = -g
Sx = 47.04t
Sy = 19.6t - 1/2gt^2

where u and v and initial and final velocities, and a and s are acceleration and distance, x and y are in the horizontal and vertical directions.

I subbed in Sy = 14.7 and got a quadratic with two solutions - t=1 and t=3, since the time of flight is 8 seconds, either solution is acceptable.
Im stuck as to what to do next. Any hep would be appreciated.

(B) Heres my sketch for this part:
http://community.webshots.com/s/image1/4/49/1/95444901reiLfQ_ph.jpg

Im totally stuck here. The given velocity is what i would have thought to be the x velocity, suggesting the particle has no y velocity - which cant be possible i think? Any help as to how to break this down would be helpful