A mass of 5 kg hangs from a cord around a light pulley. The length between the vibrator and the pulley is 2 m. (A) When the vibrator is set to a frequency of 150 hz, a standing wave with 6 loops is formed. What must be the linear mass density of the cord?(adsbygoogle = window.adsbygoogle || []).push({});

First I figured the wave length was 2/3 m because there were 6 loops over 2 m

The Wavelength is equal to velocity over frequency

2/3 = V/150

V=100 M/s

V = the squareroot of Ft (force of tension in the rope) divided by the mass of length

The Squareroot of Ft/(m/L) = V

Ft = 49

L=2/3

m=desired variable

v=100

I got .0033 kg for the answer when I plugged this all in. The correct answer is .0049. Thanks for the help

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# Homework Help: Where'd I go wrong (sound problems)

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