- #1

- 66

- 0

So far I have:

ln(x) + ln(x+1) = 1

ln(x)(x+1) = 1

e^1 = x(x+1)

e^1 = x^2 + x

This is where I get stuck.

Am I on the right track?

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- Thread starter r_swayze
- Start date

- #1

- 66

- 0

So far I have:

ln(x) + ln(x+1) = 1

ln(x)(x+1) = 1

e^1 = x(x+1)

e^1 = x^2 + x

This is where I get stuck.

Am I on the right track?

- #2

rock.freak667

Homework Helper

- 6,223

- 31

e^1 = x^2 + x

Yes this is correct. Write e^1 as just e, which is constant.

If you move it to the other side you'll get:

x

Now how do you solve the equation ax

- #3

- 66

- 0

Yes this is correct. Write e^1 as just e, which is constant.

If you move it to the other side you'll get:

x^{2}+x-e =0

Now how do you solve the equation ax^{2}+bx+c=0?

I dont think x^2 + x - e = 0 can factor out, at least not without using the quadratic formula

- #4

rock.freak667

Homework Helper

- 6,223

- 31

I dont think x^2 + x - e = 0 can factor out, at least not without using the quadratic formula

Then use the wquadratic equation formula and you'd solve for x.

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