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http://img693.imageshack.us/img693/4447/whichhitsfirst.jpg [Broken]

I have an explanation for this

From the equation of motion :

X = V0t + 1/2 a t^2

Where X is the displacement covered by the body

Let the displacement covered by the first stone X1 and the displacement covered by the second ball X2

To fall at the same time the two displacements must be equal right??

Therefore X1=X2

Therefore V0t + 1/2 g t1^2 = V0t + 1/2 g t2^2

Since the initial velocity is zero in both cases

Therefore V0t = zero

And the acceleration due to gravity (g) is constant for any bodies falling freely

Therefore 1/2* g* t1^2 =1/2 *g*t2^2

By dividing the equation by 1/2 g

Therefore t1^2 =t2^2

Therefore t1=t2

IS THAT RIGHT??

Thanks

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# Homework Help: Which hits First

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