- #1

Flucky

- 95

- 1

## Homework Statement

Which of the semi-empirical mass formula terms accounts for a drop in stability at low A and why?

## Homework Equations

B = a

_{v}A - a

_{s}A

^{[itex]\frac{2}{3}[/itex]}-a

_{c}Z(Z-1)A

^{[itex]\frac{-1}{3}[/itex]}-a

_{a}(A-2Z)

^{2}A

^{-1}± a

_{p}A

^{[itex]\frac{3}{4}[/itex]}

## The Attempt at a Solution

I'm struggling getting my head around this one.

The Coulomb term will decrease the binding energy as Z increases so I've ruled that out.

The asymmetric term decreases the binding energy as N>Z (more stable when N ≈ Z) so I've ruled that out.

All the rest are only dependent on A, so I would guess that it is the first term (volume term) that is the cause of low A instability. However the volume term increases linearly with A and it's such a dramatic change when looking at the binding energy per nucleon curve.

I can't explain why it would be the volume term if it is.

Any ideas?