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Which one is the correct equation?

  1. Aug 12, 2006 #1
    The molecular equation for the reaction between HCHO2 and K2CO3 is
    2HCHO3 +K2CO3 --> H2CO3 + 2KCHO2.

    H2CO3 will undergo further reaction to become H2O and CO2, so maybe the molelar equation can be written as 2HCHO3 +K2CO3 --> H2O + CO2 + 2KCHO2. Which of the molecular equation is the correct one?

    Then, for ionic equation, which one of the following is the correct one?
    2HCHO2 + 2K+ + CO32- --> H2CO3 + 2K+ + 2CHO2-
    or
    2HCHO2 + 2K+ + CO32- --> H2O + CO2 + 2K+ + 2CHO2-
    or
    2H+ + 2CHO2- + 2K+ + CO32- --> H2CO3 + 2K+ + 2CHO2-
    or
    2H+ + 2CHO2- + 2K+ + CO32- --> H2O + CO2 + 2K+ + 2CHO2-

    Do we need to separate the acid? But then again it is a weak acid.
    However, since this reaction is a neutralization reaction between an acid and a base, it would be weird if we don't separate the acid into ions. Technically, small percene of the acid do ionize.
     
  2. jcsd
  3. Aug 12, 2006 #2
    The second is correct, because H2CO3 doesn't exist in a solution and always dissociates in H2O and CO2.

    none are correct, since you have equal amount K+ on both sides of the arrow so they cancel each other out. But apart from that i would go for the second one.

    assume the reaction takes place completely all HCOOH will form HCOO-
     
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