Which one will have greater kinetic energy.

In summary, the kinetic energy of the sphere will be greater than the particle in circular motion, unless the sphere always faces the same direction. This is because the kinetic energy of the sphere includes both linear and rotational kinetic energy, while the particle only has linear kinetic energy.
  • #1
vkash
318
1
case 1: a particle of mass 'm' Kg is revolving in a circular path of radius 'r'.
case 2: A sphere of mass 'm' Kg is revolving in a circular path of radius 'r' . string is connected to it's centre of mass.

which one will have greater kinetic energy.
It's not home work question i ask this because recently it came in my mind.
 
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  • #2
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  • #3
tiny-tim said:
hi vkash! :smile:

https://www.physicsforums.com/library.php?do=view_item&itemid=132" = linear kinetic energy + rotational kinetic energy

= ½mv2 + ½Ic.o.m.ω2

so the KE of the sphere will be greater, unless ω = 0,

ie unless the sphere always faces the same direction :wink:
thanks!
 
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1. What is kinetic energy?

Kinetic energy is the energy an object possesses due to its motion.

2. How is kinetic energy calculated?

Kinetic energy can be calculated using the formula KE = 1/2 * m * v^2, where m is the mass of the object and v is its velocity.

3. What factors affect an object's kinetic energy?

The mass and velocity of an object are the two main factors that affect its kinetic energy. The greater the mass and velocity, the greater the kinetic energy.

4. What is the relationship between kinetic energy and potential energy?

Kinetic energy and potential energy are two forms of energy that are interrelated. As an object gains kinetic energy, it loses potential energy, and vice versa.

5. Which one will have greater kinetic energy: an object with a larger mass or an object with a higher velocity?

An object with a higher velocity will have greater kinetic energy, as it is a squared term in the kinetic energy formula. However, an object with a larger mass can also have a significant impact on its kinetic energy.

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