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Mathematics
General Math
Which probability calculation is "more correct" in Baccarat games?
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[QUOTE="bernd, post: 6820505, member: 730277"] Well, yeah. since if I add the odds of games where A wins, then that number should be As overall win likeliness. same for B and draw result. Sure, I can go and jsut do 1 million games or such, but I thought to be more precisely just evaluate every possible game and add up the winning odds for each of the 3 possible outcomes, since that should give up the msot precise answer (leaving some rounding and programming issues aside). but what I got as a result can even be explained by rounding errors, as getting like 35% of the around 45% as expected was jsut too wrong. so either there was still some big programming error in it. or my calculations were right but what I calculated wasnt the odds of a certain event happening at all. even though simplest stochastic school class material would suggest that my method should work.check all possible "paths" in the tree diagram, look how likely each one happens. and add up the probabilities of all those path probabilities that end in the desired result. however i jsut don't get, why the internet says I cant calculate this way but have to "assume" that each event (displayed beind differently likely) has equal chance of happening. and it's only jsut about how many of the total game end with A winning, B winning or draw. :-/ [/QUOTE]
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Which probability calculation is "more correct" in Baccarat games?
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