Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

While finding a second solution with wronskian for bessel

  1. Dec 20, 2009 #1
    Hello guys, i'm new here. i was working on a mathematical methods in physics book and there is a part that i dont understand. so i want to ask if anyone knows... while finding a second solution for bessel diff. eq.(for m=0) the book used wronskian method. in the method there is J^2 bin the denominator. so it becomes J^-2 and the series is made such that

    {1 - (x^2)/4 + (x^4)/64 - (x^6)/2304 + .... }^-2 = {1 + (x^2)/2 + (x^6)/32 + .....}

    the part that i didnt understand how can someone conver minus 2 power into right hand side:S. please help me, is there a general formula for this?
  2. jcsd
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?
Draft saved Draft deleted